Inner product: Difference between revisions
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== Mathematical definition == | |||
Let $V$ be a vector space over $\mathbb{F}$. | |||
Map | |||
$$ | $$ | ||
\langle \cdot, \cdot \rangle : V \times V \to \mathbb{F} | \begin{aligned} | ||
\langle \cdot, \cdot \rangle : V \times V \to \mathbb{F}\\ | |||
\quad (u, v) \mapsto \langle u, v \rangle | |||
\end{aligned} | |||
$$ | $$ | ||
is an '''inner product''' on $V$ if 4 conditions are satisfied: | |||
* '''Linearity in the 1st slot''': $\forall (u, v, w \in V, a \in \mathbb{F}), \langle u + v, w \rangle = \langle u, w \rangle + \langle v, w \rangle$ and $\langle au, v \rangle = a \langle u, v \rangle$ | |||
* '''Definiteness''': $\langle v, v \rangle = 0 \iff v = \vec 0$. | |||
* '''Positivity''': $\forall v \in V, v \neq \vec 0, \langle v, v \rangle > 0$ | |||
* '''Conjugate symmetry''': $\forall u, v \in V, \langle u, v \rangle = \overline{\langle v, u \rangle}$. | |||
<blockquote> | |||
Recall: | |||
$$\forall x\in\mathbb{R},\; x=\overline{x}$$ | |||
Hence, for real vector spaces, conjugate symmetry of an inner product becomes actual symmetry. | |||
</blockquote> | |||
<blockquote> | <blockquote> | ||
'''Warning''': confusingly, the convention in physics is often the exact opposite: an inner product is linear in the second slot and anti-linear in the first slot. | |||
</blockquote> | </blockquote> | ||
== Derived properties == | |||
=== The inner product is anti-linear in the second slot === | |||
$$ | |||
\forall u,v,w\in V, a \in \mathbb{F}: \\ | |||
\begin{cases} | |||
\langle u, v+w \rangle = \langle u, v \rangle+\langle u, w \rangle \\ | |||
\langle u, av \rangle = \overline{a}\langle u, v \rangle | |||
\end{cases} | |||
$$ | |||
'''Proof:''' | |||
For additivity: | |||
$$ | |||
\langle u, v+w \rangle = \overline{\langle v+w, u \rangle} = \overline{\langle v, u \rangle+\langle w, u \rangle} \\ | |||
= \overline{\langle v, u \rangle} + \overline{\langle w, u \rangle} = \langle u, v \rangle + \langle u, w \rangle | |||
$$ | |||
Similarly, for anti-homogeneity: | |||
$$\langle u, av \rangle = \overline{\langle av, u \rangle} = \overline{a\langle v, u \rangle} | |||
= \overline{a} \overline{\langle v, u \rangle} = \overline{a} \langle u, v \rangle$$ | |||
== See also == | == See also == | ||
[[Inner product space]] | [[Inner product space]] | ||
Latest revision as of 20:41, 30 September 2026
Mathematical definition
Let $V$ be a vector space over $\mathbb{F}$.
Map
$$ \begin{aligned} \langle \cdot, \cdot \rangle : V \times V \to \mathbb{F}\\ \quad (u, v) \mapsto \langle u, v \rangle \end{aligned} $$
is an inner product on $V$ if 4 conditions are satisfied:
- Linearity in the 1st slot: $\forall (u, v, w \in V, a \in \mathbb{F}), \langle u + v, w \rangle = \langle u, w \rangle + \langle v, w \rangle$ and $\langle au, v \rangle = a \langle u, v \rangle$
- Definiteness: $\langle v, v \rangle = 0 \iff v = \vec 0$.
- Positivity: $\forall v \in V, v \neq \vec 0, \langle v, v \rangle > 0$
- Conjugate symmetry: $\forall u, v \in V, \langle u, v \rangle = \overline{\langle v, u \rangle}$.
Recall:
$$\forall x\in\mathbb{R},\; x=\overline{x}$$
Hence, for real vector spaces, conjugate symmetry of an inner product becomes actual symmetry.
Warning: confusingly, the convention in physics is often the exact opposite: an inner product is linear in the second slot and anti-linear in the first slot.
Derived properties
The inner product is anti-linear in the second slot
$$\begin{gathered} \forall u,v,w\in V, a \in \mathbb{F}: \\ \begin{cases} \langle u, v+w \rangle = \langle u, v \rangle+\langle u, w \rangle \\ \langle u, av \rangle = \overline{a}\langle u, v \rangle \end{cases} \end{gathered}$$
Proof:
For additivity:
$$\begin{gathered} \langle u, v+w \rangle = \overline{\langle v+w, u \rangle} = \overline{\langle v, u \rangle+\langle w, u \rangle} \\ = \overline{\langle v, u \rangle} + \overline{\langle w, u \rangle} = \langle u, v \rangle + \langle u, w \rangle \end{gathered}$$
Similarly, for anti-homogeneity:
$$\langle u, av \rangle = \overline{\langle av, u \rangle} = \overline{a\langle v, u \rangle} = \overline{a} \overline{\langle v, u \rangle} = \overline{a} \langle u, v \rangle$$