Pendulum as a first-order system (Q1617): Difference between revisions

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\\frac{d\\theta}{dt}=v,\\qquad \\frac{dv}{dt}=-\\frac{g}{L}\\sin\\theta,\\qquad \\text{equilibria at }(\\theta,v)=(0,0)\\ \\text{and}\\ (\\pi,0)
 
Property / LaTeX source: \\frac{d\\theta}{dt}=v,\\qquad \\frac{dv}{dt}=-\\frac{g}{L}\\sin\\theta,\\qquad \\text{equilibria at }(\\theta,v)=(0,0)\\ \\text{and}\\ (\\pi,0) / rank
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Property / instance of: mathematical expression / rank
 
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\\begin{cases}\n\\omega=\\frac{d\\theta}{dt} \\\\\n\\frac{d\\omega}{dt}=-\\frac{g}{L}\\sin\\theta\n\\end{cases}
Property / LaTeX source: \\begin{cases}\n\\omega=\\frac{d\\theta}{dt} \\\\\n\\frac{d\\omega}{dt}=-\\frac{g}{L}\\sin\\theta\n\\end{cases} / rank
 
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From equation 2 it can be inferred that equilibria is reached at $\\theta=0$ or $\\theta=\\pi$
Property / note: From equation 2 it can be inferred that equilibria is reached at $\\theta=0$ or $\\theta=\\pi$ / rank
 
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Latest revision as of 18:30, 10 October 2026

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Pendulum as a first-order system
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    \\begin{cases}\n\\omega=\\frac{d\\theta}{dt} \\\\\n\\frac{d\\omega}{dt}=-\\frac{g}{L}\\sin\\theta\n\\end{cases}
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    From equation 2 it can be inferred that equilibria is reached at $\\theta=0$ or $\\theta=\\pi$
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