Euler's method for exponential growth and its convergence (Q1614): Difference between revisions

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y_{n+1}=(1+h)\\,y_{n}\\;\\Longrightarrow\\; y_{n}=(1+h)^{n},\\qquad \\lim_{h\\to 0}(1+h)^{1/h}=e
 
Property / LaTeX source: y_{n+1}=(1+h)\\,y_{n}\\;\\Longrightarrow\\; y_{n}=(1+h)^{n},\\qquad \\lim_{h\\to 0}(1+h)^{1/h}=e / rank
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y_{n+1}=(1+h)\\,y_{n}\\;\\Longrightarrow\\; y_{n}=(1+h)^{n},\\qquad \\lim_{h\\to 0}(1+h)^{1/h}=e
Property / LaTeX source: y_{n+1}=(1+h)\\,y_{n}\\;\\Longrightarrow\\; y_{n}=(1+h)^{n},\\qquad \\lim_{h\\to 0}(1+h)^{1/h}=e / rank
 
Normal rank

Latest revision as of 13:26, 3 September 2026

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Euler's method for exponential growth and its convergence
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    y_{n+1}=(1+h)\\,y_{n}\\;\\Longrightarrow\\; y_{n}=(1+h)^{n},\\qquad \\lim_{h\\to 0}(1+h)^{1/h}=e
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