Linearisation about an equilibrium and the eigenvalue stability criterion (Q1677): Difference between revisions

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\\mathbf{u}'=A\\mathbf{u},\\qquad A=D\\mathbf{f}(\\mathbf{x}^{*});\\qquad \\operatorname{Re}(\\lambda)<0\\ \\text{for all eigenvalues } \\lambda\\ \\Rightarrow\\ \\mathbf{x}^{*}\\ \\text{asymptotically stable}
 
Property / LaTeX source: \\mathbf{u}'=A\\mathbf{u},\\qquad A=D\\mathbf{f}(\\mathbf{x}^{*});\\qquad \\operatorname{Re}(\\lambda)<0\\ \\text{for all eigenvalues } \\lambda\\ \\Rightarrow\\ \\mathbf{x}^{*}\\ \\text{asymptotically stable} / rank
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\\mathbf{u}'=A\\mathbf{u},\\qquad A=D\\mathbf{f}(\\mathbf{x}^{*});\\qquad \\operatorname{Re}(\\lambda)<0\\ \\text{for all eigenvalues } \\lambda\\ \\Rightarrow\\ \\mathbf{x}^{*}\\ \\text{asymptotically stable}
Property / LaTeX source: \\mathbf{u}'=A\\mathbf{u},\\qquad A=D\\mathbf{f}(\\mathbf{x}^{*});\\qquad \\operatorname{Re}(\\lambda)<0\\ \\text{for all eigenvalues } \\lambda\\ \\Rightarrow\\ \\mathbf{x}^{*}\\ \\text{asymptotically stable} / rank
 
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Latest revision as of 07:28, 4 September 2026

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Linearisation about an equilibrium and the eigenvalue stability criterion
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    \\mathbf{u}'=A\\mathbf{u},\\qquad A=D\\mathbf{f}(\\mathbf{x}^{*});\\qquad \\operatorname{Re}(\\lambda)<0\\ \\text{for all eigenvalues } \\lambda\\ \\Rightarrow\\ \\mathbf{x}^{*}\\ \\text{asymptotically stable}
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