Function: Difference between revisions

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\forall x \in D: \exists y \in R, f(x)=y
\forall x \in D: \exists y \in R, f(x)=y
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<ref>{{#cite:Q2199}}</ref>


Then $f$ is a function of '''domain''' $D$ and '''range''' $R$, noted as $f: D \to R$.
Then $f$ is a function of '''domain''' $D$ and '''range''' $R$, noted as $f: D \to R$.

Revision as of 11:32, 16 October 2026

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A function is a many-to-one map between two sets.

Formal definition

Let $D,R \neq \emptyset$ be sets.

If

$$ \forall x \in D: \exists y \in R, f(x)=y $$

[1]

Then $f$ is a function of domain $D$ and range $R$, noted as $f: D \to R$.

Example:

$$ f(x)=2x^2, x \in \mathbb{C} $$

is a function, where $f: \mathbb{C} \to \mathbb{C}$

Image and preimage

Given function $f: A \to B$

If for $A_1 \subseteq A, B_1 \subseteq B$,

$$ B_1=f(A_1)=\{f(a)|\forall a \in A_1\} $$

Then $B_1$ is known as the image of $A_1$ in $B$ under $f$, and $A_1$ is known as the pre-image of $B_1$ under $f$.

[1]