Polynomial: Difference between revisions
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$x+x^{\frac{1}{2}}$ is '''not''' a polynomial as $\frac{1}{2}\notin \mathbb{N}$ | $x+x^{\frac{1}{2}}$ is '''not''' a polynomial as $\frac{1}{2}\notin \mathbb{N}$ | ||
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Revision as of 13:23, 16 October 2026
Mathematical definition
Let $P(x)$ be a mathematical function $P:\mathbb{F} \to \mathbb{F}$
If $P(x)$, through algebraic manipulation, can be written in the form of
$$P(x)=\sum_{k=0}^{n} a_k x^k, n\in\mathbb{N},a_0, a_1, \dots, a_n\in \mathbb{F}$$
where $x\in \mathbb{F}$ is an independent variable
Then $P(x)$ is a polynomial over $\mathbb{F}$
Technically, $0$ is a polynomial.
$x+x^{\frac{1}{2}}$ is not a polynomial as $\frac{1}{2}\notin \mathbb{N}$