Orthogonality: Difference between revisions
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Orthogonality generalises to an [[inner product space]]. | |||
== Mathematical definition == | |||
Let [[vector space]] $V$ be an [[inner product space]]. | |||
Two vectors $u,v\in V$ are '''orthogonal''' if $\langle u, v \rangle=0$. | |||
$u\bot v$ denotes this orthogonality. | |||
== Properties == | |||
=== $\vec 0$ is orthogonal to every vector === | |||
$$ | |||
\forall v \in V, \vec 0 \bot v | |||
$$ | |||
'''Proof''': | |||
$$ | |||
Recall [[Vector_space#Mathematical_definition|the properties of a vector space by definition]]. By additive identity, $\vec 0 +\vec 0 = \vec 0$ | |||
Therefore, | |||
$$ | |||
\langle \vec 0, u \rangle = \langle \vec 0+\vec 0, u\rangle | |||
$$ | |||
Recall the [[inner product|properties of the inner product by definition]], by linearity in the 1st slot, | |||
$$ | |||
\langle \vec 0+\vec 0, u\rangle = \langle\vec 0, u \rangle+\langle \vec 0, u\rangle | |||
$$ | |||
Subtracting $\langle \vec 0, u\rangle$ from both sides gives | |||
$$ | |||
\langle \vec 0, u \rangle=0. | |||
$$ | |||
Revision as of 14:36, 29 September 2026
Orthogonality generalises to an inner product space.
Mathematical definition
Let vector space $V$ be an inner product space.
Two vectors $u,v\in V$ are orthogonal if $\langle u, v \rangle=0$.
$u\bot v$ denotes this orthogonality.
Properties
$\vec 0$ is orthogonal to every vector
$$ \forall v \in V, \vec 0 \bot v $$
Proof:
$$ Recall the properties of a vector space by definition. By additive identity, $\vec 0 +\vec 0 = \vec 0$
Therefore,
$$ \langle \vec 0, u \rangle = \langle \vec 0+\vec 0, u\rangle $$
Recall the properties of the inner product by definition, by linearity in the 1st slot,
$$ \langle \vec 0+\vec 0, u\rangle = \langle\vec 0, u \rangle+\langle \vec 0, u\rangle $$
Subtracting $\langle \vec 0, u\rangle$ from both sides gives
$$ \langle \vec 0, u \rangle=0. $$