Integrating factor for a linear first-order equation (Q1613): Difference between revisions

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\\frac{dy}{dx}+p(x)\\,y=q(x),\\qquad \\mu(x)=e^{\\int p(x)\\,dx}\\;\\Longrightarrow\\;\\frac{d}{dx}\\bigl(\\mu(x)\\,y\\bigr)=\\mu(x)\\,q(x)
 
Property / LaTeX source: \\frac{dy}{dx}+p(x)\\,y=q(x),\\qquad \\mu(x)=e^{\\int p(x)\\,dx}\\;\\Longrightarrow\\;\\frac{d}{dx}\\bigl(\\mu(x)\\,y\\bigr)=\\mu(x)\\,q(x) / rank
Normal rank
 
Property / instance of
 
Property / instance of: mathematical expression / rank
 
Normal rank
Property / LaTeX source
 
\\frac{dy}{dx}+p(x)\\,y=q(x),\\qquad \\mu(x)=e^{\\int p(x)\\,dx}\\;\\Longrightarrow\\;\\frac{d}{dx}\\bigl(\\mu(x)\\,y\\bigr)=\\mu(x)\\,q(x)
Property / LaTeX source: \\frac{dy}{dx}+p(x)\\,y=q(x),\\qquad \\mu(x)=e^{\\int p(x)\\,dx}\\;\\Longrightarrow\\;\\frac{d}{dx}\\bigl(\\mu(x)\\,y\\bigr)=\\mu(x)\\,q(x) / rank
 
Normal rank

Revision as of 13:26, 3 September 2026

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Integrating factor for a linear first-order equation
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    \\frac{dy}{dx}+p(x)\\,y=q(x),\\qquad \\mu(x)=e^{\\int p(x)\\,dx}\\;\\Longrightarrow\\;\\frac{d}{dx}\\bigl(\\mu(x)\\,y\\bigr)=\\mu(x)\\,q(x)
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