Characteristic equation from an exponential trial solution (Q1621): Difference between revisions
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| Property / instance of: mathematical expression / rank | |||
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| Property / LaTeX source: y=e^{rx}\\ \\Rightarrow\\ (r^{2}-3r+2)\\,e^{rx}=0\\ \\Rightarrow\\ r^{2}-3r+2=(r-1)(r-2)=0 / rank | |||
| Property / instance of | |||
| Property / instance of: mathematical expression / rank | |||
Normal rank | |||
| Property / LaTeX source | |||
y=e^{rx}\\ \\Rightarrow\\ (r^{2}-3r+2)\\,e^{rx}=0\\ \\Rightarrow\\ r^{2}-3r+2=(r-1)(r-2)=0 | |||
| Property / LaTeX source: y=e^{rx}\\ \\Rightarrow\\ (r^{2}-3r+2)\\,e^{rx}=0\\ \\Rightarrow\\ r^{2}-3r+2=(r-1)(r-2)=0 / rank | |||
Normal rank | |||
Latest revision as of 13:26, 3 September 2026
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| Language | Label | Description | Also known as |
|---|---|---|---|
| English | Characteristic equation from an exponential trial solution |
No description defined |
Statements
y=e^{rx}\\ \\Rightarrow\\ (r^{2}-3r+2)\\,e^{rx}=0\\ \\Rightarrow\\ r^{2}-3r+2=(r-1)(r-2)=0
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