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Show new changes starting from 12:30, 16 October 2026
 
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13 October 2026

      04:38  Hyperplane diffhist +26 Rongzhou talk contribs

12 October 2026

 N    13:48  vector space basis definition (Q2144) 6 changes hist +2,101 [Rongzhou (6×)]
      
13:48 (cur | prev) −13 Rongzhou talk contribs (Updated the item for vector space basis definition from Special:Update)
      
11:17 (cur | prev) +2 Rongzhou talk contribs (Updated the item for vector space basis definition from Special:Update)
      
07:32 (cur | prev) +59 Rongzhou talk contribs (Updated the item for vector space base definition from Special:Update)
      
07:28 (cur | prev) +2 Rongzhou talk contribs (Updated the item for vector space base definition from Special:Update)
      
07:27 (cur | prev) +236 Rongzhou talk contribs (Added content item: vector space base definition)
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07:27 (cur | prev) +1,815 Rongzhou talk contribs (Added content item: vector space base definition)
 N    11:10  Hyperplane diffhist +794 Rongzhou talk contribs (Created page with "Let $V$ be a vector space over $\mathbb{F}$. {{#content:Q2146}} == Properties == === Inner product space === If $V$ is an inner product space over $\mathbb{F}$ and $P$ is a hyperplane of dimension $k$. $\exists \vec w \in V, b \in \mathbb{F} \Rightarrow \forall \vec u \in P, \langle \vec w, \vec u \rangle =b$ Then $\vec w$ is called the '''normal vector''' of hyperplane $P$. If it is known that $P=\left\{ \vec p + \sum_{i=1}^{k} \lambda_{i}\vec v_{i}\, |\, \v...")
      11:03  Vector subspace 2 changes hist −118 [Rongzhou (2×)]
      
11:03 (cur | prev) −136 Rongzhou talk contribs
      
07:10 (cur | prev) +18 Rongzhou talk contribs
 N    08:42  Linearly independent diffhist +594 Rongzhou talk contribs (Created page with "== Vectors == === Mathematical definition === A set of vectors $\{\vec{v}_1, \vec{v}_2, \dots, \vec{v}_n\}$ is '''linearly independent''' if $$ c_1 \vec{v}_1 + c_2 \vec{v}_2 + \cdots + c_n \vec{v}_n = \vec{0} $$ has no solution besides $$ c_1, c_2, \cdots, c_n = 0. $$ === Equivalent definition === Equivalently, it can be stated that if $$ \forall i,j \in \{1,n\} \vec v_i \neq \sum \lambda\vec v_j \\ \text{(no vector in the set can be written as a linear combinat...")